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in 'lua_call', avoid preparing a continuation when thread cannot yield.

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This commit is contained in:
Roberto Ierusalimschy 2009-03-30 15:39:20 -03:00
parent a274596ecc
commit 4e43741943
1 changed files with 8 additions and 8 deletions
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16
lapi.c
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@ -1,5 +1,5 @@
/*
** $Id: lapi.c,v 2.71 2009/03/10 17:14:37 roberto Exp roberto $
** $Id: lapi.c,v 2.72 2009/03/23 14:26:12 roberto Exp roberto $
** Lua API
** See Copyright Notice in lua.h
*/
@ -779,14 +779,14 @@ LUA_API void lua_callk (lua_State *L, int nargs, int nresults, int ctx,
api_checknelems(L, nargs+1);
checkresults(L, nargs, nresults);
func = L->top - (nargs+1);
if (k != NULL) {
L->ci->u.c.k = k;
L->ci->u.c.ctx = ctx;
L->ci->callstatus |= CIST_CTX;
luaD_call(L, func, nresults, 1);
if (k != NULL && L->nny == 0) { /* need to prepare continuation? */
L->ci->u.c.k = k; /* save continuation */
L->ci->u.c.ctx = ctx; /* save context */
L->ci->callstatus |= CIST_CTX; /* mark that call has context */
luaD_call(L, func, nresults, 1); /* do the call */
}
else
luaD_call(L, func, nresults, 0);
else /* no continuation or no yieldable */
luaD_call(L, func, nresults, 0); /* just do the call */
adjustresults(L, nresults);
lua_unlock(L);
}